| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 2.82 |
| Score | 0% | 56% |
Solve for y:
3y - 7 > -8 - 5y
| y > -\(\frac{1}{8}\) | |
| y > -\(\frac{6}{7}\) | |
| y > 1 | |
| y > \(\frac{1}{3}\) |
To solve this equation, repeatedly do the same thing to both sides of the equation until the variable is isolated on one side of the > sign and the answer on the other.
3y - 7 > -8 - 5y
3y > -8 - 5y + 7
3y + 5y > -8 + 7
8y > -1
y > \( \frac{-1}{8} \)
y > -\(\frac{1}{8}\)
If b = -4 and x = -8, what is the value of 9b(b - x)?
| -144 | |
| 144 | |
| -140 | |
| 72 |
To solve this equation, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
9b(b - x)
9(-4)(-4 + 8)
9(-4)(4)
(-36)(4)
-144
The endpoints of this line segment are at (-2, -2) and (2, 4). What is the slope-intercept equation for this line?
| y = 1\(\frac{1}{2}\)x + 1 | |
| y = 3x + 3 | |
| y = 3x - 3 | |
| y = -\(\frac{1}{2}\)x + 3 |
The slope-intercept equation for a line is y = mx + b where m is the slope and b is the y-intercept of the line. From the graph, you can see that the y-intercept (the y-value from the point where the line crosses the y-axis) is 1. The slope of this line is the change in y divided by the change in x. The endpoints of this line segment are at (-2, -2) and (2, 4) so the slope becomes:
m = \( \frac{\Delta y}{\Delta x} \) = \( \frac{(4.0) - (-2.0)}{(2) - (-2)} \) = \( \frac{6}{4} \)Plugging these values into the slope-intercept equation:
y = 1\(\frac{1}{2}\)x + 1
Which of the following is not required to define the slope-intercept equation for a line?
y-intercept |
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x-intercept |
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\({\Delta y \over \Delta x}\) |
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slope |
A line on the coordinate grid can be defined by a slope-intercept equation: y = mx + b. For a given value of x, the value of y can be determined given the slope (m) and y-intercept (b) of the line. The slope of a line is change in y over change in x, \({\Delta y \over \Delta x}\), and the y-intercept is the y-coordinate where the line crosses the vertical y-axis.
Breaking apart a quadratic expression into a pair of binomials is called:
normalizing |
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squaring |
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deconstructing |
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factoring |
To factor a quadratic expression, apply the FOIL (First, Outside, Inside, Last) method in reverse.