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|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 2.77 |
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Solve for x:
x + 9 < \( \frac{x}{6} \)
| x < -1\(\frac{1}{2}\) | |
| x < \(\frac{54}{73}\) | |
| x < 5\(\frac{5}{8}\) | |
| x < -10\(\frac{4}{5}\) |
To solve this equation, repeatedly do the same thing to both sides of the equation until the variable is isolated on one side of the < sign and the answer on the other.
x + 9 < \( \frac{x}{6} \)
6 x (x + 9) < x
(6 x x) + (6 x 9) < x
6x + 54 < x
6x + 54 - x < 0
6x - x < -54
5x < -54
x < \( \frac{-54}{5} \)
x < -10\(\frac{4}{5}\)
Which of the following is not a part of PEMDAS, the acronym for math order of operations?
division |
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exponents |
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addition |
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pairs |
When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
For this diagram, the Pythagorean theorem states that b2 = ?
c2 - a2 |
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c - a |
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c2 + a2 |
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a2 - c2 |
The Pythagorean theorem defines the relationship between the side lengths of a right triangle. The length of the hypotenuse squared (c2) is equal to the sum of the two perpendicular sides squared (a2 + b2): c2 = a2 + b2 or, solved for c, \(c = \sqrt{a + b}\)
On this circle, a line segment connecting point A to point D is called:
chord |
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diameter |
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radius |
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circumference |
A circle is a figure in which each point around its perimeter is an equal distance from the center. The radius of a circle is the distance between the center and any point along its perimeter. A chord is a line segment that connects any two points along its perimeter. The diameter of a circle is the length of a chord that passes through the center of the circle and equals twice the circle's radius (2r).
The dimensions of this cylinder are height (h) = 6 and radius (r) = 9. What is the surface area?
| 270π | |
| 24π | |
| 44π | |
| 224π |
The surface area of a cylinder is 2πr2 + 2πrh:
sa = 2πr2 + 2πrh
sa = 2π(92) + 2π(9 x 6)
sa = 2π(81) + 2π(54)
sa = (2 x 81)π + (2 x 54)π
sa = 162π + 108π
sa = 270π