ASVAB Math Knowledge Practice Test 710621 Results

Your Results Global Average
Questions 5 5
Correct 0 2.77
Score 0% 55%

Review

1

Solve for x:
x + 9 < \( \frac{x}{6} \)

44% Answer Correctly
x < -1\(\frac{1}{2}\)
x < \(\frac{54}{73}\)
x < 5\(\frac{5}{8}\)
x < -10\(\frac{4}{5}\)

Solution

To solve this equation, repeatedly do the same thing to both sides of the equation until the variable is isolated on one side of the < sign and the answer on the other.

x + 9 < \( \frac{x}{6} \)
6 x (x + 9) < x
(6 x x) + (6 x 9) < x
6x + 54 < x
6x + 54 - x < 0
6x - x < -54
5x < -54
x < \( \frac{-54}{5} \)
x < -10\(\frac{4}{5}\)


2

Which of the following is not a part of PEMDAS, the acronym for math order of operations?

88% Answer Correctly

division

exponents

addition

pairs


Solution

When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)


3

For this diagram, the Pythagorean theorem states that b2 = ?

47% Answer Correctly

c2 - a2

c - a

c2 + a2

a2 - c2


Solution

The Pythagorean theorem defines the relationship between the side lengths of a right triangle. The length of the hypotenuse squared (c2) is equal to the sum of the two perpendicular sides squared (a2 + b2): c2 = a2 + b2 or, solved for c, \(c = \sqrt{a + b}\)


4

On this circle, a line segment connecting point A to point D is called:

46% Answer Correctly

chord

diameter

radius

circumference


Solution

A circle is a figure in which each point around its perimeter is an equal distance from the center. The radius of a circle is the distance between the center and any point along its perimeter. A chord is a line segment that connects any two points along its perimeter. The diameter of a circle is the length of a chord that passes through the center of the circle and equals twice the circle's radius (2r).


5

The dimensions of this cylinder are height (h) = 6 and radius (r) = 9. What is the surface area?

48% Answer Correctly
270π
24π
44π
224π

Solution

The surface area of a cylinder is 2πr2 + 2πrh:

sa = 2πr2 + 2πrh
sa = 2π(92) + 2π(9 x 6)
sa = 2π(81) + 2π(54)
sa = (2 x 81)π + (2 x 54)π
sa = 162π + 108π
sa = 270π