When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
Solve 6c + 2c = -8c - 6z - 7 for c in terms of z.
| -\(\frac{1}{3}\)z - \(\frac{2}{3}\) | |
| 3z - 2\(\frac{1}{2}\) | |
| 1\(\frac{3}{4}\)z + \(\frac{1}{2}\) | |
| -\(\frac{4}{7}\)z - \(\frac{1}{2}\) |