When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
Solve 6c - 6c = -c - 7z + 1 for c in terms of z.
| -\(\frac{4}{5}\)z + \(\frac{4}{5}\) | |
| z + \(\frac{1}{13}\) | |
| -\(\frac{1}{7}\)z + \(\frac{1}{7}\) | |
| 4\(\frac{1}{3}\)z - 3 |