When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
Solve 8c - 4c = -7c + 6z + 2 for c in terms of z.
| -\(\frac{7}{10}\)z + \(\frac{3}{10}\) | |
| \(\frac{12}{13}\)z - \(\frac{6}{13}\) | |
| -\(\frac{1}{2}\)z - \(\frac{1}{10}\) | |
| \(\frac{2}{3}\)z + \(\frac{2}{15}\) |