ASVAB Math Knowledge Practice Test 714180 Results

Your Results Global Average
Questions 5 5
Correct 0 2.83
Score 0% 57%

Review

1

Solve for b:
-8b - 2 = -1 - 5b

59% Answer Correctly
\(\frac{1}{5}\)
\(\frac{2}{3}\)
-\(\frac{1}{3}\)
\(\frac{3}{4}\)

Solution

To solve this equation, repeatedly do the same thing to both sides of the equation until the variable is isolated on one side of the equal sign and the answer on the other.

-8b - 2 = -1 - 5b
-8b = -1 - 5b + 2
-8b + 5b = -1 + 2
-3b = 1
b = \( \frac{1}{-3} \)
b = -\(\frac{1}{3}\)


2

The dimensions of this cube are height (h) = 2, length (l) = 1, and width (w) = 9. What is the surface area?

51% Answer Correctly
62
112
78
58

Solution

The surface area of a cube is (2 x length x width) + (2 x width x height) + (2 x length x height):

sa = 2lw + 2wh + 2lh
sa = (2 x 1 x 9) + (2 x 9 x 2) + (2 x 1 x 2)
sa = (18) + (36) + (4)
sa = 58


3

The dimensions of this trapezoid are a = 5, b = 7, c = 7, d = 3, and h = 3. What is the area?

51% Answer Correctly
26
15
30
25

Solution

The area of a trapezoid is one-half the sum of the lengths of the parallel sides multiplied by the height:

a = ½(b + d)(h)
a = ½(7 + 3)(3)
a = ½(10)(3)
a = ½(30) = \( \frac{30}{2} \)
a = 15


4

If side a = 5, side b = 8, what is the length of the hypotenuse of this right triangle?

64% Answer Correctly
\( \sqrt{89} \)
\( \sqrt{74} \)
\( \sqrt{26} \)
5

Solution

According to the Pythagorean theorem, the hypotenuse squared is equal to the sum of the two perpendicular sides squared:

c2 = a2 + b2
c2 = 52 + 82
c2 = 25 + 64
c2 = 89
c = \( \sqrt{89} \)


5

If the base of this triangle is 1 and the height is 4, what is the area?

59% Answer Correctly
36
97\(\frac{1}{2}\)
20
2

Solution

The area of a triangle is equal to ½ base x height:

a = ½bh
a = ½ x 1 x 4 = \( \frac{4}{2} \) = 2