ASVAB Math Knowledge Practice Test 714511 Results

Your Results Global Average
Questions 5 5
Correct 0 3.30
Score 0% 66%

Review

1

What is 8a + 8a?

81% Answer Correctly
64a
a2
16a
0

Solution

To combine like terms, add or subtract the coefficients (the numbers that come before the variables) of terms that have the same variable raised to the same exponent.

8a + 8a = 16a


2

Which of the following statements about math operations is incorrect?

71% Answer Correctly

you can multiply monomials that have different variables and different exponents

you can subtract monomials that have the same variable and the same exponent

all of these statements are correct

you can add monomials that have the same variable and the same exponent


Solution

You can only add or subtract monomials that have the same variable and the same exponent. For example, 2a + 4a = 6a and 4a2 - a2 = 3a2 but 2a + 4b and 7a - 3b cannot be combined. However, you can multiply and divide monomials with unlike terms. For example, 2a x 6b = 12ab.


3

If a = c = 3, b = d = 9, what is the area of this rectangle?

80% Answer Correctly
9
30
27
42

Solution

The area of a rectangle is equal to its length x width:

a = l x w
a = a x b
a = 3 x 9
a = 27


4

Which of the following statements about a parallelogram is not true?

50% Answer Correctly

opposite sides and adjacent angles are equal

the area of a parallelogram is base x height

the perimeter of a parallelogram is the sum of the lengths of all sides

a parallelogram is a quadrilateral


Solution

A parallelogram is a quadrilateral with two sets of parallel sides. Opposite sides (a = c, b = d) and angles (red = red, blue = blue) are equal. The area of a parallelogram is base x height and the perimeter is the sum of the lengths of all sides (a + b + c + d).


5

The endpoints of this line segment are at (-2, 6) and (2, -6). What is the slope of this line?

46% Answer Correctly
-3
-1
\(\frac{1}{2}\)
1\(\frac{1}{2}\)

Solution

The slope of this line is the change in y divided by the change in x. The endpoints of this line segment are at (-2, 6) and (2, -6) so the slope becomes:

m = \( \frac{\Delta y}{\Delta x} \) = \( \frac{(-6.0) - (6.0)}{(2) - (-2)} \) = \( \frac{-12}{4} \)
m = -3