| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.68 |
| Score | 0% | 74% |
Simplify (9a)(2ab) + (6a2)(5b).
| 121ab2 | |
| 12ab2 | |
| 48a2b | |
| -12ab2 |
To multiply monomials, multiply the coefficients (the numbers that come before the variables) of each term, add the exponents of like variables, and multiply the different variables together.
(9a)(2ab) + (6a2)(5b)
(9 x 2)(a x a x b) + (6 x 5)(a2 x b)
(18)(a1+1 x b) + (30)(a2b)
18a2b + 30a2b
48a2b
Which of the following statements about math operations is incorrect?
all of these statements are correct |
|
you can subtract monomials that have the same variable and the same exponent |
|
you can add monomials that have the same variable and the same exponent |
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you can multiply monomials that have different variables and different exponents |
You can only add or subtract monomials that have the same variable and the same exponent. For example, 2a + 4a = 6a and 4a2 - a2 = 3a2 but 2a + 4b and 7a - 3b cannot be combined. However, you can multiply and divide monomials with unlike terms. For example, 2a x 6b = 12ab.
If BD = 29 and AD = 30, AB = ?
| 2 | |
| 7 | |
| 1 | |
| 4 |
The entire length of this line is represented by AD which is AB + BD:
AD = AB + BD
Solving for AB:AB = AD - BDIf side x = 8cm, side y = 14cm, and side z = 15cm what is the perimeter of this triangle?
| 31cm | |
| 29cm | |
| 22cm | |
| 37cm |
The perimeter of a triangle is the sum of the lengths of its sides:
p = x + y + z
p = 8cm + 14cm + 15cm = 37cm
This diagram represents two parallel lines with a transversal. If z° = 18, what is the value of a°?
| 24 | |
| 170 | |
| 142 | |
| 18 |
For parallel lines with a transversal, the following relationships apply:
Applying these relationships starting with z° = 18, the value of a° is 18.