| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 2.66 |
| Score | 0% | 53% |
Breaking apart a quadratic expression into a pair of binomials is called:
deconstructing |
|
normalizing |
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factoring |
|
squaring |
To factor a quadratic expression, apply the FOIL (First, Outside, Inside, Last) method in reverse.
Find the value of c:
-c + x = -5
6c - 4x = -8
| 1\(\frac{1}{2}\) | |
| -\(\frac{5}{23}\) | |
| 1\(\frac{32}{41}\) | |
| -14 |
You need to find the value of c so solve the first equation in terms of x:
-c + x = -5
x = -5 + c
then substitute the result (-5 - -1c) into the second equation:
6c - 4(-5 + c) = -8
6c + (-4 x -5) + (-4 x c) = -8
6c + 20 - 4c = -8
6c - 4c = -8 - 20
2c = -28
c = \( \frac{-28}{2} \)
c = -14
The endpoints of this line segment are at (-2, 1) and (2, -3). What is the slope-intercept equation for this line?
| y = 1\(\frac{1}{2}\)x + 1 | |
| y = 2x + 4 | |
| y = -x - 1 | |
| y = \(\frac{1}{2}\)x + 2 |
The slope-intercept equation for a line is y = mx + b where m is the slope and b is the y-intercept of the line. From the graph, you can see that the y-intercept (the y-value from the point where the line crosses the y-axis) is -1. The slope of this line is the change in y divided by the change in x. The endpoints of this line segment are at (-2, 1) and (2, -3) so the slope becomes:
m = \( \frac{\Delta y}{\Delta x} \) = \( \frac{(-3.0) - (1.0)}{(2) - (-2)} \) = \( \frac{-4}{4} \)Plugging these values into the slope-intercept equation:
y = -x - 1
If angle a = 30° and angle b = 33° what is the length of angle d?
| 137° | |
| 119° | |
| 150° | |
| 130° |
An exterior angle of a triangle is equal to the sum of the two interior angles that are opposite:
d° = b° + c°
To find angle c, remember that the sum of the interior angles of a triangle is 180°:
180° = a° + b° + c°
c° = 180° - a° - b°
c° = 180° - 30° - 33° = 117°
So, d° = 33° + 117° = 150°
A shortcut to get this answer is to remember that angles around a line add up to 180°:
a° + d° = 180°
d° = 180° - a°
d° = 180° - 30° = 150°
The dimensions of this cylinder are height (h) = 1 and radius (r) = 1. What is the surface area?
| 42π | |
| 4π | |
| 14π | |
| 140π |
The surface area of a cylinder is 2πr2 + 2πrh:
sa = 2πr2 + 2πrh
sa = 2π(12) + 2π(1 x 1)
sa = 2π(1) + 2π(1)
sa = (2 x 1)π + (2 x 1)π
sa = 2π + 2π
sa = 4π