When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
Solve 9c + 4c = 8c + 3z - 3 for c in terms of z.
| -1\(\frac{6}{7}\)z - 1 | |
| -z - 3 | |
| -3z + 1 | |
| -\(\frac{1}{2}\)z - 1\(\frac{1}{4}\) |