| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.18 |
| Score | 0% | 64% |
Solve for x:
6x - 8 > -3 + 3x
| x > -1\(\frac{2}{7}\) | |
| x > -8 | |
| x > 8 | |
| x > 1\(\frac{2}{3}\) |
To solve this equation, repeatedly do the same thing to both sides of the equation until the variable is isolated on one side of the > sign and the answer on the other.
6x - 8 > -3 + 3x
6x > -3 + 3x + 8
6x - 3x > -3 + 8
3x > 5
x > \( \frac{5}{3} \)
x > 1\(\frac{2}{3}\)
If side x = 12cm, side y = 14cm, and side z = 11cm what is the perimeter of this triangle?
| 37cm | |
| 34cm | |
| 29cm | |
| 26cm |
The perimeter of a triangle is the sum of the lengths of its sides:
p = x + y + z
p = 12cm + 14cm + 11cm = 37cm
If c = -4 and y = -3, what is the value of 9c(c - y)?
| -36 | |
| 216 | |
| -144 | |
| 36 |
To solve this equation, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
9c(c - y)
9(-4)(-4 + 3)
9(-4)(-1)
(-36)(-1)
36
Solve for c:
c2 - 3c - 16 = -2c + 4
| 7 or -8 | |
| 2 or -2 | |
| -4 or 5 | |
| 1 or -7 |
The first step to solve a quadratic expression that's not set to zero is to solve the equation so that it is set to zero:
c2 - 3c - 16 = -2c + 4
c2 - 3c - 16 - 4 = -2c
c2 - 3c + 2c - 20 = 0
c2 - c - 20 = 0
Next, factor the quadratic equation:
c2 - c - 20 = 0
(c + 4)(c - 5) = 0
For this expression to be true, the left side of the expression must equal zero. Therefore, either (c + 4) or (c - 5) must equal zero:
If (c + 4) = 0, c must equal -4
If (c - 5) = 0, c must equal 5
So the solution is that c = -4 or 5
If a = c = 3, b = d = 8, and the blue angle = 56°, what is the area of this parallelogram?
| 42 | |
| 24 | |
| 49 | |
| 32 |
The area of a parallelogram is equal to its length x width:
a = l x w
a = a x b
a = 3 x 8
a = 24