ASVAB Math Knowledge Practice Test 718131 Results

Your Results Global Average
Questions 5 5
Correct 0 3.27
Score 0% 65%

Review

1

If angle a = 54° and angle b = 52° what is the length of angle c?

71% Answer Correctly
74°
99°
81°
65°

Solution

The sum of the interior angles of a triangle is 180°:
180° = a° + b° + c°
c° = 180° - a° - b°
c° = 180° - 54° - 52° = 74°


2

The dimensions of this cylinder are height (h) = 3 and radius (r) = 5. What is the surface area?

48% Answer Correctly
180π
104π
80π

Solution

The surface area of a cylinder is 2πr2 + 2πrh:

sa = 2πr2 + 2πrh
sa = 2π(52) + 2π(5 x 3)
sa = 2π(25) + 2π(15)
sa = (2 x 25)π + (2 x 15)π
sa = 50π + 30π
sa = 80π


3

If the base of this triangle is 8 and the height is 9, what is the area?

58% Answer Correctly
52
54
60
36

Solution

The area of a triangle is equal to ½ base x height:

a = ½bh
a = ½ x 8 x 9 = \( \frac{72}{2} \) = 36


4

What is 9a + 6a?

81% Answer Correctly
15a
54a
15a2
54a2

Solution

To combine like terms, add or subtract the coefficients (the numbers that come before the variables) of terms that have the same variable raised to the same exponent.

9a + 6a = 15a


5

If the area of this square is 16, what is the length of one of the diagonals?

68% Answer Correctly
8\( \sqrt{2} \)
5\( \sqrt{2} \)
6\( \sqrt{2} \)
4\( \sqrt{2} \)

Solution

To find the diagonal we need to know the length of one of the square's sides. We know the area and the area of a square is the length of one side squared:

a = s2

so the length of one side of the square is:

s = \( \sqrt{a} \) = \( \sqrt{16} \) = 4

The Pythagorean theorem defines the square of the hypotenuse (diagonal) of a triangle with a right angle as the sum of the squares of the other two sides:

c2 = a2 + b2
c2 = 42 + 42
c2 = 32
c = \( \sqrt{32} \) = \( \sqrt{16 x 2} \) = \( \sqrt{16} \) \( \sqrt{2} \)
c = 4\( \sqrt{2} \)