ASVAB Math Knowledge Practice Test 718416 Results

Your Results Global Average
Questions 5 5
Correct 0 3.05
Score 0% 61%

Review

1

If the area of this square is 49, what is the length of one of the diagonals?

68% Answer Correctly
9\( \sqrt{2} \)
7\( \sqrt{2} \)
5\( \sqrt{2} \)
2\( \sqrt{2} \)

Solution

To find the diagonal we need to know the length of one of the square's sides. We know the area and the area of a square is the length of one side squared:

a = s2

so the length of one side of the square is:

s = \( \sqrt{a} \) = \( \sqrt{49} \) = 7

The Pythagorean theorem defines the square of the hypotenuse (diagonal) of a triangle with a right angle as the sum of the squares of the other two sides:

c2 = a2 + b2
c2 = 72 + 72
c2 = 98
c = \( \sqrt{98} \) = \( \sqrt{49 x 2} \) = \( \sqrt{49} \) \( \sqrt{2} \)
c = 7\( \sqrt{2} \)


2

If angle a = 40° and angle b = 43° what is the length of angle d?

56% Answer Correctly
114°
142°
118°
140°

Solution

An exterior angle of a triangle is equal to the sum of the two interior angles that are opposite:

d° = b° + c°

To find angle c, remember that the sum of the interior angles of a triangle is 180°:

180° = a° + b° + c°
c° = 180° - a° - b°
c° = 180° - 40° - 43° = 97°

So, d° = 43° + 97° = 140°

A shortcut to get this answer is to remember that angles around a line add up to 180°:

a° + d° = 180°
d° = 180° - a°
d° = 180° - 40° = 140°


3

If the length of AB equals the length of BD, point B __________ this line segment.

45% Answer Correctly

midpoints

trisects

intersects

bisects


Solution

A line segment is a portion of a line with a measurable length. The midpoint of a line segment is the point exactly halfway between the endpoints. The midpoint bisects (cuts in half) the line segment.


4

If angle a = 29° and angle b = 51° what is the length of angle c?

71% Answer Correctly
60°
70°
105°
100°

Solution

The sum of the interior angles of a triangle is 180°:
180° = a° + b° + c°
c° = 180° - a° - b°
c° = 180° - 29° - 51° = 100°


5

Simplify (2a)(3ab) + (9a2)(4b).

65% Answer Correctly
65ab2
42ab2
30a2b
42a2b

Solution

To multiply monomials, multiply the coefficients (the numbers that come before the variables) of each term, add the exponents of like variables, and multiply the different variables together.

(2a)(3ab) + (9a2)(4b)
(2 x 3)(a x a x b) + (9 x 4)(a2 x b)
(6)(a1+1 x b) + (36)(a2b)
6a2b + 36a2b
42a2b