When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
Solve 3c - 6c = -7c + 9z - 8 for c in terms of z.
| -\(\frac{3}{5}\)z + \(\frac{3}{5}\) | |
| 1\(\frac{3}{11}\)z + \(\frac{6}{11}\) | |
| \(\frac{8}{15}\)z + \(\frac{7}{15}\) | |
| 1\(\frac{1}{2}\)z - \(\frac{4}{5}\) |