When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
Solve -8c - 4c = 8c - 9y + 2 for c in terms of y.
| 1\(\frac{5}{6}\)y + 1 | |
| \(\frac{5}{16}\)y - \(\frac{1}{8}\) | |
| \(\frac{12}{13}\)y - \(\frac{3}{13}\) | |
| -\(\frac{1}{9}\)y - \(\frac{1}{9}\) |