When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
Solve -5c + 6c = -8c + 8y - 3 for c in terms of y.
| 11y + 5 | |
| -\(\frac{3}{8}\)y + \(\frac{5}{16}\) | |
| \(\frac{2}{3}\)y - 1 | |
| -\(\frac{3}{5}\)y + \(\frac{4}{5}\) |