When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
Solve 5c + 8c = 2c + 2y + 1 for c in terms of y.
| 1\(\frac{5}{6}\)y - 1\(\frac{1}{6}\) | |
| \(\frac{5}{17}\)y + \(\frac{8}{17}\) | |
| -2y + \(\frac{1}{3}\) | |
| 4y - 8 |