ASVAB Math Knowledge Practice Test 721902 Results

Your Results Global Average
Questions 5 5
Correct 0 3.28
Score 0% 66%

Review

1

The formula for the area of a circle is which of the following?

77% Answer Correctly

a = π d

a = π r2

a = π d2

a = π r


Solution

The circumference of a circle is the distance around its perimeter and equals π (approx. 3.14159) x diameter: c = π d. The area of a circle is π x (radius)2 : a = π r2.


2

A trapezoid is a quadrilateral with one set of __________ sides.

70% Answer Correctly

equal angle

equal length

right angle

parallel


Solution

A trapezoid is a quadrilateral with one set of parallel sides.


3

If the area of this square is 36, what is the length of one of the diagonals?

68% Answer Correctly
8\( \sqrt{2} \)
6\( \sqrt{2} \)
3\( \sqrt{2} \)
2\( \sqrt{2} \)

Solution

To find the diagonal we need to know the length of one of the square's sides. We know the area and the area of a square is the length of one side squared:

a = s2

so the length of one side of the square is:

s = \( \sqrt{a} \) = \( \sqrt{36} \) = 6

The Pythagorean theorem defines the square of the hypotenuse (diagonal) of a triangle with a right angle as the sum of the squares of the other two sides:

c2 = a2 + b2
c2 = 62 + 62
c2 = 72
c = \( \sqrt{72} \) = \( \sqrt{36 x 2} \) = \( \sqrt{36} \) \( \sqrt{2} \)
c = 6\( \sqrt{2} \)


4

The formula for volume of a cube in terms of height (h), length (l), and width (w) is which of the following?

67% Answer Correctly

h2 x l2 x w2

2lw x 2wh + 2lh

h x l x w

lw x wh + lh


Solution

A cube is a rectangular solid box with a height (h), length (l), and width (w). The volume is h x l x w and the surface area is 2lw x 2wh + 2lh.


5

Solve for y:
-5y - 9 = \( \frac{y}{-4} \)

46% Answer Correctly
-1\(\frac{17}{19}\)
-1
-1\(\frac{2}{19}\)
-2\(\frac{2}{23}\)

Solution

To solve this equation, repeatedly do the same thing to both sides of the equation until the variable is isolated on one side of the equal sign and the answer on the other.

-5y - 9 = \( \frac{y}{-4} \)
-4 x (-5y - 9) = y
(-4 x -5y) + (-4 x -9) = y
20y + 36 = y
20y + 36 - y = 0
20y - y = -36
19y = -36
y = \( \frac{-36}{19} \)
y = -1\(\frac{17}{19}\)