| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.28 |
| Score | 0% | 66% |
The formula for the area of a circle is which of the following?
a = π d |
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a = π r2 |
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a = π d2 |
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a = π r |
The circumference of a circle is the distance around its perimeter and equals π (approx. 3.14159) x diameter: c = π d. The area of a circle is π x (radius)2 : a = π r2.
A trapezoid is a quadrilateral with one set of __________ sides.
equal angle |
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equal length |
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right angle |
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parallel |
A trapezoid is a quadrilateral with one set of parallel sides.
If the area of this square is 36, what is the length of one of the diagonals?
| 8\( \sqrt{2} \) | |
| 6\( \sqrt{2} \) | |
| 3\( \sqrt{2} \) | |
| 2\( \sqrt{2} \) |
To find the diagonal we need to know the length of one of the square's sides. We know the area and the area of a square is the length of one side squared:
a = s2
so the length of one side of the square is:
s = \( \sqrt{a} \) = \( \sqrt{36} \) = 6
The Pythagorean theorem defines the square of the hypotenuse (diagonal) of a triangle with a right angle as the sum of the squares of the other two sides:
c2 = a2 + b2
c2 = 62 + 62
c2 = 72
c = \( \sqrt{72} \) = \( \sqrt{36 x 2} \) = \( \sqrt{36} \) \( \sqrt{2} \)
c = 6\( \sqrt{2} \)
The formula for volume of a cube in terms of height (h), length (l), and width (w) is which of the following?
h2 x l2 x w2 |
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2lw x 2wh + 2lh |
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h x l x w |
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lw x wh + lh |
A cube is a rectangular solid box with a height (h), length (l), and width (w). The volume is h x l x w and the surface area is 2lw x 2wh + 2lh.
Solve for y:
-5y - 9 = \( \frac{y}{-4} \)
| -1\(\frac{17}{19}\) | |
| -1 | |
| -1\(\frac{2}{19}\) | |
| -2\(\frac{2}{23}\) |
To solve this equation, repeatedly do the same thing to both sides of the equation until the variable is isolated on one side of the equal sign and the answer on the other.
-5y - 9 = \( \frac{y}{-4} \)
-4 x (-5y - 9) = y
(-4 x -5y) + (-4 x -9) = y
20y + 36 = y
20y + 36 - y = 0
20y - y = -36
19y = -36
y = \( \frac{-36}{19} \)
y = -1\(\frac{17}{19}\)