ASVAB Math Knowledge Practice Test 722626

Question 2 of 5
Two Variables

When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)

Solve 4a + 2a = -6a + 5z + 2 for a in terms of z.

-\(\frac{1}{2}\)z + \(\frac{3}{8}\)
\(\frac{3}{10}\)z + \(\frac{1}{5}\)
\(\frac{9}{14}\)z + \(\frac{3}{14}\)
-1\(\frac{6}{7}\)z - 1