| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.08 |
| Score | 0% | 62% |
If c = -8 and y = 2, what is the value of -2c(c - y)?
| 12 | |
| -160 | |
| 56 | |
| -99 |
To solve this equation, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
-2c(c - y)
-2(-8)(-8 - 2)
-2(-8)(-10)
(16)(-10)
-160
The endpoints of this line segment are at (-2, 2) and (2, -2). What is the slope of this line?
| -1 | |
| \(\frac{1}{2}\) | |
| 1\(\frac{1}{2}\) | |
| 2\(\frac{1}{2}\) |
The slope of this line is the change in y divided by the change in x. The endpoints of this line segment are at (-2, 2) and (2, -2) so the slope becomes:
m = \( \frac{\Delta y}{\Delta x} \) = \( \frac{(-2.0) - (2.0)}{(2) - (-2)} \) = \( \frac{-4}{4} \)Which of the following expressions contains exactly two terms?
quadratic |
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polynomial |
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binomial |
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monomial |
A monomial contains one term, a binomial contains two terms, and a polynomial contains more than two terms.
Which of the following is not true about both rectangles and squares?
the area is length x width |
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the perimeter is the sum of the lengths of all four sides |
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the lengths of all sides are equal |
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all interior angles are right angles |
A rectangle is a parallelogram containing four right angles. Opposite sides (a = c, b = d) are equal and the perimeter is the sum of the lengths of all sides (a + b + c + d) or, comonly, 2 x length x width. The area of a rectangle is length x width. A square is a rectangle with four equal length sides. The perimeter of a square is 4 x length of one side (4s) and the area is the length of one side squared (s2).
For this diagram, the Pythagorean theorem states that b2 = ?
a2 - c2 |
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c2 + a2 |
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c - a |
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c2 - a2 |
The Pythagorean theorem defines the relationship between the side lengths of a right triangle. The length of the hypotenuse squared (c2) is equal to the sum of the two perpendicular sides squared (a2 + b2): c2 = a2 + b2 or, solved for c, \(c = \sqrt{a + b}\)