| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 2.52 |
| Score | 0% | 50% |
Solve for z:
z2 - 5z - 13 = -z - 1
| 6 or -5 | |
| -2 or 6 | |
| 8 or 3 | |
| -3 or -3 |
The first step to solve a quadratic expression that's not set to zero is to solve the equation so that it is set to zero:
z2 - 5z - 13 = -z - 1
z2 - 5z - 13 + 1 = -z
z2 - 5z + z - 12 = 0
z2 - 4z - 12 = 0
Next, factor the quadratic equation:
z2 - 4z - 12 = 0
(z + 2)(z - 6) = 0
For this expression to be true, the left side of the expression must equal zero. Therefore, either (z + 2) or (z - 6) must equal zero:
If (z + 2) = 0, z must equal -2
If (z - 6) = 0, z must equal 6
So the solution is that z = -2 or 6
The dimensions of this cylinder are height (h) = 8 and radius (r) = 6. What is the surface area?
| 160π | |
| 16π | |
| 104π | |
| 168π |
The surface area of a cylinder is 2πr2 + 2πrh:
sa = 2πr2 + 2πrh
sa = 2π(62) + 2π(6 x 8)
sa = 2π(36) + 2π(48)
sa = (2 x 36)π + (2 x 48)π
sa = 72π + 96π
sa = 168π
Solve 2b - b = 8b - 8z - 4 for b in terms of z.
| 1\(\frac{1}{6}\)z + \(\frac{2}{3}\) | |
| -\(\frac{2}{5}\)z + 1\(\frac{3}{5}\) | |
| -1\(\frac{1}{3}\)z + 1\(\frac{2}{3}\) | |
| 3\(\frac{1}{2}\)z - 3\(\frac{1}{2}\) |
To solve this equation, isolate the variable for which you are solving (b) on one side of the equation and put everything else on the other side.
2b - z = 8b - 8z - 4
2b = 8b - 8z - 4 + z
2b - 8b = -8z - 4 + z
-6b = -7z - 4
b = \( \frac{-7z - 4}{-6} \)
b = \( \frac{-7z}{-6} \) + \( \frac{-4}{-6} \)
b = 1\(\frac{1}{6}\)z + \(\frac{2}{3}\)
The formula for the area of a circle is which of the following?
a = π r |
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a = π d2 |
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a = π d |
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a = π r2 |
The circumference of a circle is the distance around its perimeter and equals π (approx. 3.14159) x diameter: c = π d. The area of a circle is π x (radius)2 : a = π r2.
If the length of AB equals the length of BD, point B __________ this line segment.
trisects |
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intersects |
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midpoints |
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bisects |
A line segment is a portion of a line with a measurable length. The midpoint of a line segment is the point exactly halfway between the endpoints. The midpoint bisects (cuts in half) the line segment.