ASVAB Math Knowledge Practice Test 724382 Results

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Questions 5 5
Correct 0 2.52
Score 0% 50%

Review

1

Solve for z:
z2 - 5z - 13 = -z - 1

48% Answer Correctly
6 or -5
-2 or 6
8 or 3
-3 or -3

Solution

The first step to solve a quadratic expression that's not set to zero is to solve the equation so that it is set to zero:

z2 - 5z - 13 = -z - 1
z2 - 5z - 13 + 1 = -z
z2 - 5z + z - 12 = 0
z2 - 4z - 12 = 0

Next, factor the quadratic equation:

z2 - 4z - 12 = 0
(z + 2)(z - 6) = 0

For this expression to be true, the left side of the expression must equal zero. Therefore, either (z + 2) or (z - 6) must equal zero:

If (z + 2) = 0, z must equal -2
If (z - 6) = 0, z must equal 6

So the solution is that z = -2 or 6


2

The dimensions of this cylinder are height (h) = 8 and radius (r) = 6. What is the surface area?

48% Answer Correctly
160π
16π
104π
168π

Solution

The surface area of a cylinder is 2πr2 + 2πrh:

sa = 2πr2 + 2πrh
sa = 2π(62) + 2π(6 x 8)
sa = 2π(36) + 2π(48)
sa = (2 x 36)π + (2 x 48)π
sa = 72π + 96π
sa = 168π


3

Solve 2b - b = 8b - 8z - 4 for b in terms of z.

34% Answer Correctly
1\(\frac{1}{6}\)z + \(\frac{2}{3}\)
-\(\frac{2}{5}\)z + 1\(\frac{3}{5}\)
-1\(\frac{1}{3}\)z + 1\(\frac{2}{3}\)
3\(\frac{1}{2}\)z - 3\(\frac{1}{2}\)

Solution

To solve this equation, isolate the variable for which you are solving (b) on one side of the equation and put everything else on the other side.

2b - z = 8b - 8z - 4
2b = 8b - 8z - 4 + z
2b - 8b = -8z - 4 + z
-6b = -7z - 4
b = \( \frac{-7z - 4}{-6} \)
b = \( \frac{-7z}{-6} \) + \( \frac{-4}{-6} \)
b = 1\(\frac{1}{6}\)z + \(\frac{2}{3}\)


4

The formula for the area of a circle is which of the following?

77% Answer Correctly

a = π r

a = π d2

a = π d

a = π r2


Solution

The circumference of a circle is the distance around its perimeter and equals π (approx. 3.14159) x diameter: c = π d. The area of a circle is π x (radius)2 : a = π r2.


5

If the length of AB equals the length of BD, point B __________ this line segment.

45% Answer Correctly

trisects

intersects

midpoints

bisects


Solution

A line segment is a portion of a line with a measurable length. The midpoint of a line segment is the point exactly halfway between the endpoints. The midpoint bisects (cuts in half) the line segment.