ASVAB Math Knowledge Practice Test 725145 Results

Your Results Global Average
Questions 5 5
Correct 0 2.82
Score 0% 56%

Review

1

Solve for a:
-6a + 6 < -2 + 9a

55% Answer Correctly
a < -6
a < \(\frac{8}{15}\)
a < -1\(\frac{3}{5}\)
a < 1\(\frac{1}{5}\)

Solution

To solve this equation, repeatedly do the same thing to both sides of the equation until the variable is isolated on one side of the < sign and the answer on the other.

-6a + 6 < -2 + 9a
-6a < -2 + 9a - 6
-6a - 9a < -2 - 6
-15a < -8
a < \( \frac{-8}{-15} \)
a < \(\frac{8}{15}\)


2

A(n) __________ is two expressions separated by an equal sign.

76% Answer Correctly

formula

expression

problem

equation


Solution

An equation is two expressions separated by an equal sign. The key to solving equations is to repeatedly do the same thing to both sides of the equation until the variable is isolated on one side of the equal sign and the answer on the other.


3

If the length of AB equals the length of BD, point B __________ this line segment.

45% Answer Correctly

intersects

bisects

midpoints

trisects


Solution

A line segment is a portion of a line with a measurable length. The midpoint of a line segment is the point exactly halfway between the endpoints. The midpoint bisects (cuts in half) the line segment.


4

On this circle, a line segment connecting point A to point D is called:

46% Answer Correctly

circumference

chord

radius

diameter


Solution

A circle is a figure in which each point around its perimeter is an equal distance from the center. The radius of a circle is the distance between the center and any point along its perimeter. A chord is a line segment that connects any two points along its perimeter. The diameter of a circle is the length of a chord that passes through the center of the circle and equals twice the circle's radius (2r).


5

Solve for b:
-2b + 3 = 2 + b

59% Answer Correctly
\(\frac{1}{2}\)
-\(\frac{2}{5}\)
1\(\frac{4}{5}\)
\(\frac{1}{3}\)

Solution

To solve this equation, repeatedly do the same thing to both sides of the equation until the variable is isolated on one side of the equal sign and the answer on the other.

-2b + 3 = 2 + b
-2b = 2 + b - 3
-2b - b = 2 - 3
-3b = -1
b = \( \frac{-1}{-3} \)
b = \(\frac{1}{3}\)