ASVAB Math Knowledge Practice Test 725629

Question 5 of 5
Two Variables

When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)

Solve 2b - 2b = 6b - 8z - 2 for b in terms of z.

13z - 7
1\(\frac{1}{2}\)z + \(\frac{1}{2}\)
z - 1
\(\frac{1}{8}\)z - \(\frac{1}{2}\)