ASVAB Math Knowledge Practice Test 726105 Results

Your Results Global Average
Questions 5 5
Correct 0 3.41
Score 0% 68%

Review

1

Which types of triangles will always have at least two sides of equal length?

54% Answer Correctly

equilateral and isosceles

isosceles and right

equilateral and right

equilateral, isosceles and right


Solution

An isosceles triangle has two sides of equal length. An equilateral triangle has three sides of equal length. In a right triangle, two sides meet at a right angle.


2

A trapezoid is a quadrilateral with one set of __________ sides.

70% Answer Correctly

parallel

right angle

equal length

equal angle


Solution

A trapezoid is a quadrilateral with one set of parallel sides.


3

Which of the following is not true about both rectangles and squares?

63% Answer Correctly

all interior angles are right angles

the area is length x width

the lengths of all sides are equal

the perimeter is the sum of the lengths of all four sides


Solution

A rectangle is a parallelogram containing four right angles. Opposite sides (a = c, b = d) are equal and the perimeter is the sum of the lengths of all sides (a + b + c + d) or, comonly, 2 x length x width. The area of a rectangle is length x width. A square is a rectangle with four equal length sides. The perimeter of a square is 4 x length of one side (4s) and the area is the length of one side squared (s2).


4

If the area of this square is 25, what is the length of one of the diagonals?

68% Answer Correctly
9\( \sqrt{2} \)
5\( \sqrt{2} \)
8\( \sqrt{2} \)
3\( \sqrt{2} \)

Solution

To find the diagonal we need to know the length of one of the square's sides. We know the area and the area of a square is the length of one side squared:

a = s2

so the length of one side of the square is:

s = \( \sqrt{a} \) = \( \sqrt{25} \) = 5

The Pythagorean theorem defines the square of the hypotenuse (diagonal) of a triangle with a right angle as the sum of the squares of the other two sides:

c2 = a2 + b2
c2 = 52 + 52
c2 = 50
c = \( \sqrt{50} \) = \( \sqrt{25 x 2} \) = \( \sqrt{25} \) \( \sqrt{2} \)
c = 5\( \sqrt{2} \)


5

Simplify 3a x 8b.

86% Answer Correctly
24ab
24a2b2
11ab
24\( \frac{a}{b} \)

Solution

To multiply monomials, multiply the coefficients (the numbers that come before the variables) of each term, add the exponents of like variables, and multiply the different variables together.

3a x 8b = (3 x 8) (a x b) = 24ab