When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
Solve 8c - c = 5c + 4z + 3 for c in terms of z.
| \(\frac{5}{6}\)z + 1\(\frac{1}{6}\) | |
| 1\(\frac{1}{5}\)z + \(\frac{3}{10}\) | |
| \(\frac{1}{4}\)z - \(\frac{1}{4}\) | |
| 1\(\frac{2}{3}\)z + 1 |