ASVAB Math Knowledge Practice Test 726260 Results

Your Results Global Average
Questions 5 5
Correct 0 3.01
Score 0% 60%

Review

1

Which of the following is not true about both rectangles and squares?

63% Answer Correctly

the area is length x width

all interior angles are right angles

the lengths of all sides are equal

the perimeter is the sum of the lengths of all four sides


Solution

A rectangle is a parallelogram containing four right angles. Opposite sides (a = c, b = d) are equal and the perimeter is the sum of the lengths of all sides (a + b + c + d) or, comonly, 2 x length x width. The area of a rectangle is length x width. A square is a rectangle with four equal length sides. The perimeter of a square is 4 x length of one side (4s) and the area is the length of one side squared (s2).


2

If side a = 2, side b = 3, what is the length of the hypotenuse of this right triangle?

63% Answer Correctly
\( \sqrt{34} \)
\( \sqrt{98} \)
\( \sqrt{13} \)
\( \sqrt{45} \)

Solution

According to the Pythagorean theorem, the hypotenuse squared is equal to the sum of the two perpendicular sides squared:

c2 = a2 + b2
c2 = 22 + 32
c2 = 4 + 9
c2 = 13
c = \( \sqrt{13} \)


3

Simplify (6a)(9ab) + (6a2)(4b).

65% Answer Correctly
78a2b
150ab2
30a2b
-30a2b

Solution

To multiply monomials, multiply the coefficients (the numbers that come before the variables) of each term, add the exponents of like variables, and multiply the different variables together.

(6a)(9ab) + (6a2)(4b)
(6 x 9)(a x a x b) + (6 x 4)(a2 x b)
(54)(a1+1 x b) + (24)(a2b)
54a2b + 24a2b
78a2b


4

A(n) __________ is to a parallelogram as a square is to a rectangle.

51% Answer Correctly

triangle

trapezoid

rhombus

quadrilateral


Solution

A rhombus is a parallelogram with four equal-length sides. A square is a rectangle with four equal-length sides.


5

Solve for a:
-7a + 5 = -7 - 2a

58% Answer Correctly
3
2\(\frac{2}{5}\)
-1\(\frac{1}{2}\)
1\(\frac{1}{7}\)

Solution

To solve this equation, repeatedly do the same thing to both sides of the equation until the variable is isolated on one side of the equal sign and the answer on the other.

-7a + 5 = -7 - 2a
-7a = -7 - 2a - 5
-7a + 2a = -7 - 5
-5a = -12
a = \( \frac{-12}{-5} \)
a = 2\(\frac{2}{5}\)