ASVAB Math Knowledge Practice Test 726627

Question 4 of 5
Two Variables

When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)

Solve -6a + 8a = 6a - 2z - 3 for a in terms of z.

-5\(\frac{1}{2}\)z + 4\(\frac{1}{2}\)
2z - \(\frac{1}{3}\)
-6\(\frac{1}{2}\)z - 4\(\frac{1}{2}\)
\(\frac{5}{6}\)z + \(\frac{1}{4}\)