When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
Solve a - 4a = 8a + z + 1 for a in terms of z.
| 3\(\frac{1}{5}\)z - 1\(\frac{3}{5}\) | |
| -z - \(\frac{3}{13}\) | |
| -\(\frac{5}{7}\)z - \(\frac{1}{7}\) | |
| -z + 2 |