| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 2.43 |
| Score | 0% | 49% |
Simplify (y + 7)(y + 7)
| 16 | |
| y2 - 14y + 49 | |
| y2 + 14y + 49 | |
| y2 - 49 |
To multiply binomials, use the FOIL method. FOIL stands for First, Outside, Inside, Last and refers to the position of each term in the parentheses:
(y + 7)(y + 7)
(y x y) + (y x 7) + (7 x y) + (7 x 7)
y2 + 7y + 7y + 49
y2 + 14y + 49
The endpoints of this line segment are at (-2, -1) and (2, 1). What is the slope-intercept equation for this line?
| y = -3x + 2 | |
| y = \(\frac{1}{2}\)x + 0 | |
| y = \(\frac{1}{2}\)x - 3 | |
| y = -2\(\frac{1}{2}\)x - 1 |
The slope-intercept equation for a line is y = mx + b where m is the slope and b is the y-intercept of the line. From the graph, you can see that the y-intercept (the y-value from the point where the line crosses the y-axis) is 0. The slope of this line is the change in y divided by the change in x. The endpoints of this line segment are at (-2, -1) and (2, 1) so the slope becomes:
m = \( \frac{\Delta y}{\Delta x} \) = \( \frac{(1.0) - (-1.0)}{(2) - (-2)} \) = \( \frac{2}{4} \)Plugging these values into the slope-intercept equation:
y = \(\frac{1}{2}\)x + 0
Solve for c:
-9c + 7 < -4 + 2c
| c < -1\(\frac{2}{7}\) | |
| c < -\(\frac{7}{9}\) | |
| c < \(\frac{5}{7}\) | |
| c < 1 |
To solve this equation, repeatedly do the same thing to both sides of the equation until the variable is isolated on one side of the < sign and the answer on the other.
-9c + 7 < -4 + 2c
-9c < -4 + 2c - 7
-9c - 2c < -4 - 7
-11c < -11
c < \( \frac{-11}{-11} \)
c < 1
Solve for a:
-7a - 6 < \( \frac{a}{-7} \)
| a < 2\(\frac{10}{11}\) | |
| a < -\(\frac{7}{8}\) | |
| a < -\(\frac{6}{17}\) | |
| a < -\(\frac{3}{8}\) |
To solve this equation, repeatedly do the same thing to both sides of the equation until the variable is isolated on one side of the < sign and the answer on the other.
-7a - 6 < \( \frac{a}{-7} \)
-7 x (-7a - 6) < a
(-7 x -7a) + (-7 x -6) < a
49a + 42 < a
49a + 42 - a < 0
49a - a < -42
48a < -42
a < \( \frac{-42}{48} \)
a < -\(\frac{7}{8}\)
Find the value of a:
-9a + y = 2
-5a + y = -5
| 3 | |
| -1\(\frac{3}{4}\) | |
| -37 | |
| -\(\frac{25}{28}\) |
You need to find the value of a so solve the first equation in terms of y:
-9a + y = 2
y = 2 + 9a
then substitute the result (2 - -9a) into the second equation:
-5a + 1(2 + 9a) = -5
-5a + (1 x 2) + (1 x 9a) = -5
-5a + 2 + 9a = -5
-5a + 9a = -5 - 2
4a = -7
a = \( \frac{-7}{4} \)
a = -1\(\frac{3}{4}\)