| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.18 |
| Score | 0% | 64% |
A right angle measures:
180° |
|
45° |
|
90° |
|
360° |
A right angle measures 90 degrees and is the intersection of two perpendicular lines. In diagrams, a right angle is indicated by a small box completing a square with the perpendicular lines.
The dimensions of this trapezoid are a = 4, b = 7, c = 7, d = 6, and h = 3. What is the area?
| 30 | |
| 19\(\frac{1}{2}\) | |
| 24 | |
| 18 |
The area of a trapezoid is one-half the sum of the lengths of the parallel sides multiplied by the height:
a = ½(b + d)(h)
a = ½(7 + 6)(3)
a = ½(13)(3)
a = ½(39) = \( \frac{39}{2} \)
a = 19\(\frac{1}{2}\)
If angle a = 52° and angle b = 28° what is the length of angle d?
| 128° | |
| 148° | |
| 132° | |
| 111° |
An exterior angle of a triangle is equal to the sum of the two interior angles that are opposite:
d° = b° + c°
To find angle c, remember that the sum of the interior angles of a triangle is 180°:
180° = a° + b° + c°
c° = 180° - a° - b°
c° = 180° - 52° - 28° = 100°
So, d° = 28° + 100° = 128°
A shortcut to get this answer is to remember that angles around a line add up to 180°:
a° + d° = 180°
d° = 180° - a°
d° = 180° - 52° = 128°
Solve for a:
2a - 2 > 5 + a
| a > \(\frac{8}{9}\) | |
| a > 7 | |
| a > \(\frac{3}{5}\) | |
| a > \(\frac{1}{2}\) |
To solve this equation, repeatedly do the same thing to both sides of the equation until the variable is isolated on one side of the > sign and the answer on the other.
2a - 2 > 5 + a
2a > 5 + a + 2
2a - a > 5 + 2
a > 7
If a = c = 8, b = d = 5, and the blue angle = 50°, what is the area of this parallelogram?
| 40 | |
| 9 | |
| 3 | |
| 15 |
The area of a parallelogram is equal to its length x width:
a = l x w
a = a x b
a = 8 x 5
a = 40