ASVAB Math Knowledge Practice Test 7288

Question 4 of 5
Two Variables

When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)

Solve -4b - 3b = 8b + 2y - 5 for b in terms of y.

-1\(\frac{5}{6}\)y + \(\frac{1}{6}\)
-\(\frac{5}{12}\)y + \(\frac{5}{12}\)
-\(\frac{3}{13}\)y + \(\frac{6}{13}\)
-\(\frac{6}{7}\)y + 1\(\frac{2}{7}\)