ASVAB Math Knowledge Practice Test 729290 Results

Your Results Global Average
Questions 5 5
Correct 0 2.77
Score 0% 55%

Review

1

Which types of triangles will always have at least two sides of equal length?

54% Answer Correctly

equilateral and right

equilateral, isosceles and right

isosceles and right

equilateral and isosceles


Solution

An isosceles triangle has two sides of equal length. An equilateral triangle has three sides of equal length. In a right triangle, two sides meet at a right angle.


2

On this circle, a line segment connecting point A to point D is called:

46% Answer Correctly

diameter

radius

circumference

chord


Solution

A circle is a figure in which each point around its perimeter is an equal distance from the center. The radius of a circle is the distance between the center and any point along its perimeter. A chord is a line segment that connects any two points along its perimeter. The diameter of a circle is the length of a chord that passes through the center of the circle and equals twice the circle's radius (2r).


3

Solve -6c - 7c = 9c - 5x + 3 for c in terms of x.

34% Answer Correctly
-2\(\frac{1}{5}\)x + 1\(\frac{1}{5}\)
-1\(\frac{6}{7}\)x + \(\frac{6}{7}\)
-x + \(\frac{2}{7}\)
-\(\frac{2}{15}\)x - \(\frac{1}{5}\)

Solution

To solve this equation, isolate the variable for which you are solving (c) on one side of the equation and put everything else on the other side.

-6c - 7x = 9c - 5x + 3
-6c = 9c - 5x + 3 + 7x
-6c - 9c = -5x + 3 + 7x
-15c = 2x + 3
c = \( \frac{2x + 3}{-15} \)
c = \( \frac{2x}{-15} \) + \( \frac{3}{-15} \)
c = -\(\frac{2}{15}\)x - \(\frac{1}{5}\)


4

If a = c = 8, b = d = 1, and the blue angle = 68°, what is the area of this parallelogram?

66% Answer Correctly
10
2
8
64

Solution

The area of a parallelogram is equal to its length x width:

a = l x w
a = a x b
a = 8 x 1
a = 8


5

If AD = 20 and BD = 15, AB = ?

76% Answer Correctly
13
5
12
6

Solution

The entire length of this line is represented by AD which is AB + BD:

AD = AB + BD

Solving for AB:

AB = AD - BD
AB = 20 - 15
AB = 5