ASVAB Math Knowledge Practice Test 730758 Results

Your Results Global Average
Questions 5 5
Correct 0 2.98
Score 0% 60%

Review

1

What is 7a - 8a?

80% Answer Correctly
-1a
-a2
a2
56a

Solution

To combine like terms, add or subtract the coefficients (the numbers that come before the variables) of terms that have the same variable raised to the same exponent.

7a - 8a = -1a


2

Which of the following statements about a parallelogram is not true?

50% Answer Correctly

opposite sides and adjacent angles are equal

the area of a parallelogram is base x height

a parallelogram is a quadrilateral

the perimeter of a parallelogram is the sum of the lengths of all sides


Solution

A parallelogram is a quadrilateral with two sets of parallel sides. Opposite sides (a = c, b = d) and angles (red = red, blue = blue) are equal. The area of a parallelogram is base x height and the perimeter is the sum of the lengths of all sides (a + b + c + d).


3

Which of the following is not required to define the slope-intercept equation for a line?

42% Answer Correctly

y-intercept

slope

\({\Delta y \over \Delta x}\)

x-intercept


Solution

A line on the coordinate grid can be defined by a slope-intercept equation: y = mx + b. For a given value of x, the value of y can be determined given the slope (m) and y-intercept (b) of the line. The slope of a line is change in y over change in x, \({\Delta y \over \Delta x}\), and the y-intercept is the y-coordinate where the line crosses the vertical y-axis.


4

If the base of this triangle is 8 and the height is 6, what is the area?

59% Answer Correctly
42
39
18
24

Solution

The area of a triangle is equal to ½ base x height:

a = ½bh
a = ½ x 8 x 6 = \( \frac{48}{2} \) = 24


5

If the area of this square is 49, what is the length of one of the diagonals?

68% Answer Correctly
7\( \sqrt{2} \)
6\( \sqrt{2} \)
8\( \sqrt{2} \)
\( \sqrt{2} \)

Solution

To find the diagonal we need to know the length of one of the square's sides. We know the area and the area of a square is the length of one side squared:

a = s2

so the length of one side of the square is:

s = \( \sqrt{a} \) = \( \sqrt{49} \) = 7

The Pythagorean theorem defines the square of the hypotenuse (diagonal) of a triangle with a right angle as the sum of the squares of the other two sides:

c2 = a2 + b2
c2 = 72 + 72
c2 = 98
c = \( \sqrt{98} \) = \( \sqrt{49 x 2} \) = \( \sqrt{49} \) \( \sqrt{2} \)
c = 7\( \sqrt{2} \)