| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 2.98 |
| Score | 0% | 60% |
What is 7a - 8a?
| -1a | |
| -a2 | |
| a2 | |
| 56a |
To combine like terms, add or subtract the coefficients (the numbers that come before the variables) of terms that have the same variable raised to the same exponent.
7a - 8a = -1a
Which of the following statements about a parallelogram is not true?
opposite sides and adjacent angles are equal |
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the area of a parallelogram is base x height |
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a parallelogram is a quadrilateral |
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the perimeter of a parallelogram is the sum of the lengths of all sides |
A parallelogram is a quadrilateral with two sets of parallel sides. Opposite sides (a = c, b = d) and angles (red = red, blue = blue) are equal. The area of a parallelogram is base x height and the perimeter is the sum of the lengths of all sides (a + b + c + d).
Which of the following is not required to define the slope-intercept equation for a line?
y-intercept |
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slope |
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\({\Delta y \over \Delta x}\) |
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x-intercept |
A line on the coordinate grid can be defined by a slope-intercept equation: y = mx + b. For a given value of x, the value of y can be determined given the slope (m) and y-intercept (b) of the line. The slope of a line is change in y over change in x, \({\Delta y \over \Delta x}\), and the y-intercept is the y-coordinate where the line crosses the vertical y-axis.
If the base of this triangle is 8 and the height is 6, what is the area?
| 42 | |
| 39 | |
| 18 | |
| 24 |
The area of a triangle is equal to ½ base x height:
a = ½bh
a = ½ x 8 x 6 = \( \frac{48}{2} \) = 24
If the area of this square is 49, what is the length of one of the diagonals?
| 7\( \sqrt{2} \) | |
| 6\( \sqrt{2} \) | |
| 8\( \sqrt{2} \) | |
| \( \sqrt{2} \) |
To find the diagonal we need to know the length of one of the square's sides. We know the area and the area of a square is the length of one side squared:
a = s2
so the length of one side of the square is:
s = \( \sqrt{a} \) = \( \sqrt{49} \) = 7
The Pythagorean theorem defines the square of the hypotenuse (diagonal) of a triangle with a right angle as the sum of the squares of the other two sides:
c2 = a2 + b2
c2 = 72 + 72
c2 = 98
c = \( \sqrt{98} \) = \( \sqrt{49 x 2} \) = \( \sqrt{49} \) \( \sqrt{2} \)
c = 7\( \sqrt{2} \)