ASVAB Math Knowledge Practice Test 731090 Results

Your Results Global Average
Questions 5 5
Correct 0 3.06
Score 0% 61%

Review

1

Simplify 7a x 2b.

85% Answer Correctly
9ab
14ab
14\( \frac{b}{a} \)
14\( \frac{a}{b} \)

Solution

To multiply monomials, multiply the coefficients (the numbers that come before the variables) of each term, add the exponents of like variables, and multiply the different variables together.

7a x 2b = (7 x 2) (a x b) = 14ab


2

Solve for a:
9a + 8 = \( \frac{a}{2} \)

46% Answer Correctly
\(\frac{7}{9}\)
\(\frac{4}{5}\)
1\(\frac{5}{31}\)
-\(\frac{16}{17}\)

Solution

To solve this equation, repeatedly do the same thing to both sides of the equation until the variable is isolated on one side of the equal sign and the answer on the other.

9a + 8 = \( \frac{a}{2} \)
2 x (9a + 8) = a
(2 x 9a) + (2 x 8) = a
18a + 16 = a
18a + 16 - a = 0
18a - a = -16
17a = -16
a = \( \frac{-16}{17} \)
a = -\(\frac{16}{17}\)


3

Simplify (2a)(3ab) - (6a2)(4b).

62% Answer Correctly
-18a2b
30a2b
30ab2
50ab2

Solution

To multiply monomials, multiply the coefficients (the numbers that come before the variables) of each term, add the exponents of like variables, and multiply the different variables together.

(2a)(3ab) - (6a2)(4b)
(2 x 3)(a x a x b) - (6 x 4)(a2 x b)
(6)(a1+1 x b) - (24)(a2b)
6a2b - 24a2b
-18a2b


4

If a = c = 1, b = d = 9, what is the area of this rectangle?

79% Answer Correctly
7
6
9
40

Solution

The area of a rectangle is equal to its length x width:

a = l x w
a = a x b
a = 1 x 9
a = 9


5

Solve -3a + 3a = 9a + 2y + 8 for a in terms of y.

34% Answer Correctly
y - 1\(\frac{1}{4}\)
-\(\frac{1}{4}\)y - 1\(\frac{1}{2}\)
\(\frac{1}{12}\)y - \(\frac{2}{3}\)
-1\(\frac{1}{5}\)y + \(\frac{4}{5}\)

Solution

To solve this equation, isolate the variable for which you are solving (a) on one side of the equation and put everything else on the other side.

-3a + 3y = 9a + 2y + 8
-3a = 9a + 2y + 8 - 3y
-3a - 9a = 2y + 8 - 3y
-12a = -y + 8
a = \( \frac{-y + 8}{-12} \)
a = \( \frac{-y}{-12} \) + \( \frac{8}{-12} \)
a = \(\frac{1}{12}\)y - \(\frac{2}{3}\)