When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
Solve 6c + 8c = -c + 8y - 3 for c in terms of y.
| -1\(\frac{3}{4}\)y - 1 | |
| \(\frac{7}{16}\)y + \(\frac{9}{16}\) | |
| y - \(\frac{3}{7}\) | |
| 6y - 1\(\frac{1}{2}\) |