ASVAB Math Knowledge Practice Test 7345 Results

Your Results Global Average
Questions 5 5
Correct 0 3.32
Score 0% 66%

Review

1

The dimensions of this trapezoid are a = 6, b = 7, c = 8, d = 6, and h = 4. What is the area?

50% Answer Correctly
25
12
26
19\(\frac{1}{2}\)

Solution

The area of a trapezoid is one-half the sum of the lengths of the parallel sides multiplied by the height:

a = ½(b + d)(h)
a = ½(7 + 6)(4)
a = ½(13)(4)
a = ½(52) = \( \frac{52}{2} \)
a = 26


2

A quadrilateral is a shape with __________ sides.

90% Answer Correctly

2

4

5

3


Solution

A quadrilateral is a shape with four sides. The perimeter of a quadrilateral is the sum of the lengths of its four sides.


3

On this circle, line segment AB is the:

70% Answer Correctly

radius

chord

circumference

diameter


Solution

A circle is a figure in which each point around its perimeter is an equal distance from the center. The radius of a circle is the distance between the center and any point along its perimeter. A chord is a line segment that connects any two points along its perimeter. The diameter of a circle is the length of a chord that passes through the center of the circle and equals twice the circle's radius (2r).


4

Solve for y:
y2 - 2y - 15 = 0

57% Answer Correctly
5 or 5
-6 or -9
5 or -5
-3 or 5

Solution

The first step to solve a quadratic equation that's set to zero is to factor the quadratic equation:

y2 - 2y - 15 = 0
(y + 3)(y - 5) = 0

For this expression to be true, the left side of the expression must equal zero. Therefore, either (y + 3) or (y - 5) must equal zero:

If (y + 3) = 0, y must equal -3
If (y - 5) = 0, y must equal 5

So the solution is that y = -3 or 5


5

If side a = 2, side b = 6, what is the length of the hypotenuse of this right triangle?

63% Answer Correctly
\( \sqrt{50} \)
\( \sqrt{45} \)
5
\( \sqrt{40} \)

Solution

According to the Pythagorean theorem, the hypotenuse squared is equal to the sum of the two perpendicular sides squared:

c2 = a2 + b2
c2 = 22 + 62
c2 = 4 + 36
c2 = 40
c = \( \sqrt{40} \)