| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.20 |
| Score | 0% | 64% |
Simplify (3a)(5ab) - (8a2)(2b).
| -1a2b | |
| -a2b | |
| 80a2b | |
| 31a2b |
To multiply monomials, multiply the coefficients (the numbers that come before the variables) of each term, add the exponents of like variables, and multiply the different variables together.
(3a)(5ab) - (8a2)(2b)
(3 x 5)(a x a x b) - (8 x 2)(a2 x b)
(15)(a1+1 x b) - (16)(a2b)
15a2b - 16a2b
-1a2b
If the base of this triangle is 3 and the height is 4, what is the area?
| 112\(\frac{1}{2}\) | |
| 35 | |
| 6 | |
| 82\(\frac{1}{2}\) |
The area of a triangle is equal to ½ base x height:
a = ½bh
a = ½ x 3 x 4 = \( \frac{12}{2} \) = 6
If side a = 2, side b = 1, what is the length of the hypotenuse of this right triangle?
| \( \sqrt{74} \) | |
| \( \sqrt{26} \) | |
| \( \sqrt{37} \) | |
| \( \sqrt{5} \) |
According to the Pythagorean theorem, the hypotenuse squared is equal to the sum of the two perpendicular sides squared:
c2 = a2 + b2
c2 = 22 + 12
c2 = 4 + 1
c2 = 5
c = \( \sqrt{5} \)
Solve for c:
-9c - 3 = \( \frac{c}{7} \)
| \(\frac{45}{62}\) | |
| 1\(\frac{1}{47}\) | |
| 2\(\frac{2}{15}\) | |
| -\(\frac{21}{64}\) |
To solve this equation, repeatedly do the same thing to both sides of the equation until the variable is isolated on one side of the equal sign and the answer on the other.
-9c - 3 = \( \frac{c}{7} \)
7 x (-9c - 3) = c
(7 x -9c) + (7 x -3) = c
-63c - 21 = c
-63c - 21 - c = 0
-63c - c = 21
-64c = 21
c = \( \frac{21}{-64} \)
c = -\(\frac{21}{64}\)
A quadrilateral is a shape with __________ sides.
2 |
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5 |
|
3 |
|
4 |
A quadrilateral is a shape with four sides. The perimeter of a quadrilateral is the sum of the lengths of its four sides.