ASVAB Math Knowledge Practice Test 734948 Results

Your Results Global Average
Questions 5 5
Correct 0 3.17
Score 0% 63%

Review

1

Solve for b:
b2 - 2b - 5 = b - 1

49% Answer Correctly
9 or 6
-1 or 4
1 or 1
6 or -1

Solution

The first step to solve a quadratic expression that's not set to zero is to solve the equation so that it is set to zero:

b2 - 2b - 5 = b - 1
b2 - 2b - 5 + 1 = b
b2 - 2b - b - 4 = 0
b2 - 3b - 4 = 0

Next, factor the quadratic equation:

b2 - 3b - 4 = 0
(b + 1)(b - 4) = 0

For this expression to be true, the left side of the expression must equal zero. Therefore, either (b + 1) or (b - 4) must equal zero:

If (b + 1) = 0, b must equal -1
If (b - 4) = 0, b must equal 4

So the solution is that b = -1 or 4


2

If side x = 5cm, side y = 5cm, and side z = 10cm what is the perimeter of this triangle?

85% Answer Correctly
20cm
38cm
28cm
25cm

Solution

The perimeter of a triangle is the sum of the lengths of its sides:

p = x + y + z
p = 5cm + 5cm + 10cm = 20cm


3

If the base of this triangle is 4 and the height is 3, what is the area?

58% Answer Correctly
40\(\frac{1}{2}\)
17\(\frac{1}{2}\)
6
24

Solution

The area of a triangle is equal to ½ base x height:

a = ½bh
a = ½ x 4 x 3 = \( \frac{12}{2} \) = 6


4

If BD = 6 and AD = 15, AB = ?

76% Answer Correctly
9
1
20
8

Solution

The entire length of this line is represented by AD which is AB + BD:

AD = AB + BD

Solving for AB:

AB = AD - BD
AB = 15 - 6
AB = 9


5

The dimensions of this cylinder are height (h) = 2 and radius (r) = 2. What is the surface area?

48% Answer Correctly
120π
16π
198π
132π

Solution

The surface area of a cylinder is 2πr2 + 2πrh:

sa = 2πr2 + 2πrh
sa = 2π(22) + 2π(2 x 2)
sa = 2π(4) + 2π(4)
sa = (2 x 4)π + (2 x 4)π
sa = 8π + 8π
sa = 16π