| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.17 |
| Score | 0% | 63% |
Solve for b:
b2 - 2b - 5 = b - 1
| 9 or 6 | |
| -1 or 4 | |
| 1 or 1 | |
| 6 or -1 |
The first step to solve a quadratic expression that's not set to zero is to solve the equation so that it is set to zero:
b2 - 2b - 5 = b - 1
b2 - 2b - 5 + 1 = b
b2 - 2b - b - 4 = 0
b2 - 3b - 4 = 0
Next, factor the quadratic equation:
b2 - 3b - 4 = 0
(b + 1)(b - 4) = 0
For this expression to be true, the left side of the expression must equal zero. Therefore, either (b + 1) or (b - 4) must equal zero:
If (b + 1) = 0, b must equal -1
If (b - 4) = 0, b must equal 4
So the solution is that b = -1 or 4
If side x = 5cm, side y = 5cm, and side z = 10cm what is the perimeter of this triangle?
| 20cm | |
| 38cm | |
| 28cm | |
| 25cm |
The perimeter of a triangle is the sum of the lengths of its sides:
p = x + y + z
p = 5cm + 5cm + 10cm = 20cm
If the base of this triangle is 4 and the height is 3, what is the area?
| 40\(\frac{1}{2}\) | |
| 17\(\frac{1}{2}\) | |
| 6 | |
| 24 |
The area of a triangle is equal to ½ base x height:
a = ½bh
a = ½ x 4 x 3 = \( \frac{12}{2} \) = 6
If BD = 6 and AD = 15, AB = ?
| 9 | |
| 1 | |
| 20 | |
| 8 |
The entire length of this line is represented by AD which is AB + BD:
AD = AB + BD
Solving for AB:AB = AD - BDThe dimensions of this cylinder are height (h) = 2 and radius (r) = 2. What is the surface area?
| 120π | |
| 16π | |
| 198π | |
| 132π |
The surface area of a cylinder is 2πr2 + 2πrh:
sa = 2πr2 + 2πrh
sa = 2π(22) + 2π(2 x 2)
sa = 2π(4) + 2π(4)
sa = (2 x 4)π + (2 x 4)π
sa = 8π + 8π
sa = 16π