| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.20 |
| Score | 0% | 64% |
On this circle, line segment AB is the:
radius |
|
chord |
|
diameter |
|
circumference |
A circle is a figure in which each point around its perimeter is an equal distance from the center. The radius of a circle is the distance between the center and any point along its perimeter. A chord is a line segment that connects any two points along its perimeter. The diameter of a circle is the length of a chord that passes through the center of the circle and equals twice the circle's radius (2r).
If BD = 8 and AD = 16, AB = ?
| 8 | |
| 15 | |
| 1 | |
| 17 |
The entire length of this line is represented by AD which is AB + BD:
AD = AB + BD
Solving for AB:AB = AD - BDSimplify (y + 2)(y - 5)
| y2 + 7y + 10 | |
| y2 + 3y - 10 | |
| y2 - 7y + 10 | |
| y2 - 3y - 10 |
To multiply binomials, use the FOIL method. FOIL stands for First, Outside, Inside, Last and refers to the position of each term in the parentheses:
(y + 2)(y - 5)
(y x y) + (y x -5) + (2 x y) + (2 x -5)
y2 - 5y + 2y - 10
y2 - 3y - 10
If the area of this square is 16, what is the length of one of the diagonals?
| 5\( \sqrt{2} \) | |
| 4\( \sqrt{2} \) | |
| 6\( \sqrt{2} \) | |
| \( \sqrt{2} \) |
To find the diagonal we need to know the length of one of the square's sides. We know the area and the area of a square is the length of one side squared:
a = s2
so the length of one side of the square is:
s = \( \sqrt{a} \) = \( \sqrt{16} \) = 4
The Pythagorean theorem defines the square of the hypotenuse (diagonal) of a triangle with a right angle as the sum of the squares of the other two sides:
c2 = a2 + b2
c2 = 42 + 42
c2 = 32
c = \( \sqrt{32} \) = \( \sqrt{16 x 2} \) = \( \sqrt{16} \) \( \sqrt{2} \)
c = 4\( \sqrt{2} \)
If the length of AB equals the length of BD, point B __________ this line segment.
bisects |
|
midpoints |
|
trisects |
|
intersects |
A line segment is a portion of a line with a measurable length. The midpoint of a line segment is the point exactly halfway between the endpoints. The midpoint bisects (cuts in half) the line segment.