When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
Solve 2c + 8c = -8c - 3x + 5 for c in terms of x.
| -1\(\frac{1}{10}\)x + \(\frac{1}{2}\) | |
| -1\(\frac{3}{8}\)x + \(\frac{3}{4}\) | |
| \(\frac{2}{3}\)x - \(\frac{2}{3}\) | |
| \(\frac{6}{13}\)x + \(\frac{5}{13}\) |