ASVAB Math Knowledge Practice Test 737035 Results

Your Results Global Average
Questions 5 5
Correct 0 2.95
Score 0% 59%

Review

1

On this circle, a line segment connecting point A to point D is called:

46% Answer Correctly

circumference

diameter

radius

chord


Solution

A circle is a figure in which each point around its perimeter is an equal distance from the center. The radius of a circle is the distance between the center and any point along its perimeter. A chord is a line segment that connects any two points along its perimeter. The diameter of a circle is the length of a chord that passes through the center of the circle and equals twice the circle's radius (2r).


2

Which of the following is not required to define the slope-intercept equation for a line?

42% Answer Correctly

\({\Delta y \over \Delta x}\)

y-intercept

x-intercept

slope


Solution

A line on the coordinate grid can be defined by a slope-intercept equation: y = mx + b. For a given value of x, the value of y can be determined given the slope (m) and y-intercept (b) of the line. The slope of a line is change in y over change in x, \({\Delta y \over \Delta x}\), and the y-intercept is the y-coordinate where the line crosses the vertical y-axis.


3

When two lines intersect, adjacent angles are __________ (they add up to 180°) and angles across from either other are __________ (they're equal).

60% Answer Correctly

vertical, supplementary

obtuse, acute

supplementary, vertical

acute, obtuse


Solution

Angles around a line add up to 180°. Angles around a point add up to 360°. When two lines intersect, adjacent angles are supplementary (they add up to 180°) and angles across from either other are vertical (they're equal).


4

What is 5a + 2a?

81% Answer Correctly
3
7a2
7a
3a2

Solution

To combine like terms, add or subtract the coefficients (the numbers that come before the variables) of terms that have the same variable raised to the same exponent.

5a + 2a = 7a


5

Simplify (3a)(2ab) + (8a2)(2b).

65% Answer Correctly
22a2b
10ab2
-10a2b
50ab2

Solution

To multiply monomials, multiply the coefficients (the numbers that come before the variables) of each term, add the exponents of like variables, and multiply the different variables together.

(3a)(2ab) + (8a2)(2b)
(3 x 2)(a x a x b) + (8 x 2)(a2 x b)
(6)(a1+1 x b) + (16)(a2b)
6a2b + 16a2b
22a2b