When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
Solve 2c - 7c = -4c - 2z + 6 for c in terms of z.
| 3\(\frac{2}{3}\)z + 1\(\frac{1}{3}\) | |
| -\(\frac{1}{9}\)z + \(\frac{2}{9}\) | |
| -\(\frac{1}{3}\)z + \(\frac{2}{9}\) | |
| \(\frac{5}{6}\)z + 1 |