ASVAB Math Knowledge Practice Test 738747 Results

Your Results Global Average
Questions 5 5
Correct 0 3.83
Score 0% 77%

Review

1

Solve for c:
4c + 8 = -9 - 5c

59% Answer Correctly
2
2\(\frac{2}{3}\)
4
-1\(\frac{8}{9}\)

Solution

To solve this equation, repeatedly do the same thing to both sides of the equation until the variable is isolated on one side of the equal sign and the answer on the other.

4c + 8 = -9 - 5c
4c = -9 - 5c - 8
4c + 5c = -9 - 8
9c = -17
c = \( \frac{-17}{9} \)
c = -1\(\frac{8}{9}\)


2

Simplify 8a x 4b.

86% Answer Correctly
32ab
32\( \frac{b}{a} \)
32\( \frac{a}{b} \)
12ab

Solution

To multiply monomials, multiply the coefficients (the numbers that come before the variables) of each term, add the exponents of like variables, and multiply the different variables together.

8a x 4b = (8 x 4) (a x b) = 32ab


3

If the area of this square is 1, what is the length of one of the diagonals?

68% Answer Correctly
8\( \sqrt{2} \)
\( \sqrt{2} \)
6\( \sqrt{2} \)
9\( \sqrt{2} \)

Solution

To find the diagonal we need to know the length of one of the square's sides. We know the area and the area of a square is the length of one side squared:

a = s2

so the length of one side of the square is:

s = \( \sqrt{a} \) = \( \sqrt{1} \) = 1

The Pythagorean theorem defines the square of the hypotenuse (diagonal) of a triangle with a right angle as the sum of the squares of the other two sides:

c2 = a2 + b2
c2 = 12 + 12
c2 = 2
c = \( \sqrt{2} \)


4

If a = 7, b = 9, c = 8, and d = 3, what is the perimeter of this quadrilateral?

88% Answer Correctly
17
18
12
27

Solution

Perimeter is equal to the sum of the four sides:

p = a + b + c + d
p = 7 + 9 + 8 + 3
p = 27


5

What is 7a + 3a?

81% Answer Correctly
a2
4
21a
10a

Solution

To combine like terms, add or subtract the coefficients (the numbers that come before the variables) of terms that have the same variable raised to the same exponent.

7a + 3a = 10a