When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
Solve -4c + 2c = -5c - 8z - 3 for c in terms of z.
| -10z - 3 | |
| 1\(\frac{5}{8}\)z - \(\frac{1}{8}\) | |
| 2\(\frac{1}{6}\)z + 1\(\frac{1}{3}\) | |
| 2z + 2 |