When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
Solve 4c + 4c = 8c - 9z - 1 for c in terms of z.
| -z - 1 | |
| -\(\frac{3}{10}\)z - \(\frac{1}{5}\) | |
| 3\(\frac{1}{4}\)z + \(\frac{1}{4}\) | |
| z + 6 |