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| Questions | 5 | 5 |
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Solve for x:
2x - 4 = 6 - x
| \(\frac{3}{4}\) | |
| 3\(\frac{1}{3}\) | |
| -1\(\frac{1}{2}\) | |
| -1\(\frac{1}{5}\) |
To solve this equation, repeatedly do the same thing to both sides of the equation until the variable is isolated on one side of the equal sign and the answer on the other.
2x - 4 = 6 - x
2x = 6 - x + 4
2x + x = 6 + 4
3x = 10
x = \( \frac{10}{3} \)
x = 3\(\frac{1}{3}\)
For this diagram, the Pythagorean theorem states that b2 = ?
c2 + a2 |
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c - a |
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a2 - c2 |
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c2 - a2 |
The Pythagorean theorem defines the relationship between the side lengths of a right triangle. The length of the hypotenuse squared (c2) is equal to the sum of the two perpendicular sides squared (a2 + b2): c2 = a2 + b2 or, solved for c, \(c = \sqrt{a + b}\)
Breaking apart a quadratic expression into a pair of binomials is called:
deconstructing |
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normalizing |
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squaring |
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factoring |
To factor a quadratic expression, apply the FOIL (First, Outside, Inside, Last) method in reverse.
Solve -2a - a = -8a - 9y + 1 for a in terms of y.
| -1\(\frac{1}{6}\)y + 1\(\frac{1}{2}\) | |
| -1\(\frac{1}{3}\)y + \(\frac{1}{6}\) | |
| y + 7 | |
| \(\frac{9}{17}\)y + \(\frac{1}{17}\) |
To solve this equation, isolate the variable for which you are solving (a) on one side of the equation and put everything else on the other side.
-2a - y = -8a - 9y + 1
-2a = -8a - 9y + 1 + y
-2a + 8a = -9y + 1 + y
6a = -8y + 1
a = \( \frac{-8y + 1}{6} \)
a = \( \frac{-8y}{6} \) + \( \frac{1}{6} \)
a = -1\(\frac{1}{3}\)y + \(\frac{1}{6}\)
What is 8a6 - 6a6?
| 2 | |
| 48a12 | |
| 2a12 | |
| 2a6 |
To combine like terms, add or subtract the coefficients (the numbers that come before the variables) of terms that have the same variable raised to the same exponent.
8a6 - 6a6 = 2a6