ASVAB Math Knowledge Practice Test 741777 Results

Your Results Global Average
Questions 5 5
Correct 0 3.66
Score 0% 73%

Review

1

This diagram represents two parallel lines with a transversal. If x° = 144, what is the value of z°?

73% Answer Correctly
15
36
14
16

Solution

For parallel lines with a transversal, the following relationships apply:

  • angles in the same position on different parallel lines equal each other (a° = w°, b° = x°, c° = z°, d° = y°)
  • alternate interior angles are equal (a° = z°, b° = y°, c° = w°, d° = x°)
  • all acute angles (a° = c° = w° = z°) and all obtuse angles (b° = d° = x° = y°) equal each other
  • same-side interior angles are supplementary and add up to 180° (e.g. a° + d° = 180°, d° + c° = 180°)

Applying these relationships starting with x° = 144, the value of z° is 36.


2

To multiply binomials, use the FOIL method. Which of the following is not a part of the FOIL method?

83% Answer Correctly

Odd

First

Inside

Last


Solution

To multiply binomials, use the FOIL method. FOIL stands for First, Outside, Inside, Last and refers to the position of each term in the parentheses.


3

If BD = 25 and AD = 30, AB = ?

75% Answer Correctly
5
4
8
1

Solution

The entire length of this line is represented by AD which is AB + BD:

AD = AB + BD

Solving for AB:

AB = AD - BD
AB = 30 - 25
AB = 5


4

Order the following types of angle from least number of degrees to most number of degrees.

75% Answer Correctly

right, obtuse, acute

acute, right, obtuse

acute, obtuse, right

right, acute, obtuse


Solution

An acute angle measures less than 90°, a right angle measures 90°, and an obtuse angle measures more than 90°.


5

Solve for z:
-5z - 5 = -1 + 7z

59% Answer Correctly
\(\frac{3}{4}\)
1\(\frac{3}{4}\)
-\(\frac{1}{3}\)
-1\(\frac{2}{7}\)

Solution

To solve this equation, repeatedly do the same thing to both sides of the equation until the variable is isolated on one side of the equal sign and the answer on the other.

-5z - 5 = -1 + 7z
-5z = -1 + 7z + 5
-5z - 7z = -1 + 5
-12z = 4
z = \( \frac{4}{-12} \)
z = -\(\frac{1}{3}\)