ASVAB Math Knowledge Practice Test 742977 Results

Your Results Global Average
Questions 5 5
Correct 0 3.16
Score 0% 63%

Review

1

For this diagram, the Pythagorean theorem states that b2 = ?

47% Answer Correctly

c2 - a2

c2 + a2

c - a

a2 - c2


Solution

The Pythagorean theorem defines the relationship between the side lengths of a right triangle. The length of the hypotenuse squared (c2) is equal to the sum of the two perpendicular sides squared (a2 + b2): c2 = a2 + b2 or, solved for c, \(c = \sqrt{a + b}\)


2

A quadrilateral is a shape with __________ sides.

90% Answer Correctly

2

5

3

4


Solution

A quadrilateral is a shape with four sides. The perimeter of a quadrilateral is the sum of the lengths of its four sides.


3

Solve for c:
c2 - 2c + 6 = c + 4

48% Answer Correctly
2 or 2
7 or -3
1 or 2
6 or -1

Solution

The first step to solve a quadratic expression that's not set to zero is to solve the equation so that it is set to zero:

c2 - 2c + 6 = c + 4
c2 - 2c + 6 - 4 = c
c2 - 2c - c + 2 = 0
c2 - 3c + 2 = 0

Next, factor the quadratic equation:

c2 - 3c + 2 = 0
(c - 1)(c - 2) = 0

For this expression to be true, the left side of the expression must equal zero. Therefore, either (c - 1) or (c - 2) must equal zero:

If (c - 1) = 0, c must equal 1
If (c - 2) = 0, c must equal 2

So the solution is that c = 1 or 2


4

To multiply binomials, use the FOIL method. Which of the following is not a part of the FOIL method?

83% Answer Correctly

First

Last

Odd

Inside


Solution

To multiply binomials, use the FOIL method. FOIL stands for First, Outside, Inside, Last and refers to the position of each term in the parentheses.


5

Solve for a:
8a + 7 < \( \frac{a}{2} \)

44% Answer Correctly
a < -\(\frac{14}{15}\)
a < -\(\frac{45}{82}\)
a < \(\frac{7}{64}\)
a < 1\(\frac{5}{22}\)

Solution

To solve this equation, repeatedly do the same thing to both sides of the equation until the variable is isolated on one side of the < sign and the answer on the other.

8a + 7 < \( \frac{a}{2} \)
2 x (8a + 7) < a
(2 x 8a) + (2 x 7) < a
16a + 14 < a
16a + 14 - a < 0
16a - a < -14
15a < -14
a < \( \frac{-14}{15} \)
a < -\(\frac{14}{15}\)