| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.51 |
| Score | 0% | 70% |
What is the circumference of a circle with a radius of 15?
| 30π | |
| 14π | |
| 17π | |
| 24π |
The formula for circumference is circle diameter x π. Circle diameter is 2 x radius:
c = πd
c = π(2 * r)
c = π(2 * 15)
c = 30π
A coordinate grid is composed of which of the following?
all of these |
|
x-axis |
|
origin |
|
y-axis |
The coordinate grid is composed of a horizontal x-axis and a vertical y-axis. The center of the grid, where the x-axis and y-axis meet, is called the origin.
If the area of this square is 25, what is the length of one of the diagonals?
| 5\( \sqrt{2} \) | |
| 9\( \sqrt{2} \) | |
| 7\( \sqrt{2} \) | |
| 2\( \sqrt{2} \) |
To find the diagonal we need to know the length of one of the square's sides. We know the area and the area of a square is the length of one side squared:
a = s2
so the length of one side of the square is:
s = \( \sqrt{a} \) = \( \sqrt{25} \) = 5
The Pythagorean theorem defines the square of the hypotenuse (diagonal) of a triangle with a right angle as the sum of the squares of the other two sides:
c2 = a2 + b2
c2 = 52 + 52
c2 = 50
c = \( \sqrt{50} \) = \( \sqrt{25 x 2} \) = \( \sqrt{25} \) \( \sqrt{2} \)
c = 5\( \sqrt{2} \)
If the base of this triangle is 9 and the height is 6, what is the area?
| 36 | |
| 24 | |
| 42 | |
| 27 |
The area of a triangle is equal to ½ base x height:
a = ½bh
a = ½ x 9 x 6 = \( \frac{54}{2} \) = 27
When two lines intersect, adjacent angles are __________ (they add up to 180°) and angles across from either other are __________ (they're equal).
supplementary, vertical |
|
obtuse, acute |
|
acute, obtuse |
|
vertical, supplementary |
Angles around a line add up to 180°. Angles around a point add up to 360°. When two lines intersect, adjacent angles are supplementary (they add up to 180°) and angles across from either other are vertical (they're equal).