ASVAB Math Knowledge Practice Test 743736 Results

Your Results Global Average
Questions 5 5
Correct 0 3.22
Score 0% 64%

Review

1

A right angle measures:

90% Answer Correctly

180°

90°

360°

45°


Solution

A right angle measures 90 degrees and is the intersection of two perpendicular lines. In diagrams, a right angle is indicated by a small box completing a square with the perpendicular lines.


2

Solve for b:
8b + 7 > \( \frac{b}{4} \)

44% Answer Correctly
b > 1\(\frac{1}{7}\)
b > -\(\frac{28}{31}\)
b > -1\(\frac{7}{13}\)
b > 1\(\frac{5}{7}\)

Solution

To solve this equation, repeatedly do the same thing to both sides of the equation until the variable is isolated on one side of the > sign and the answer on the other.

8b + 7 > \( \frac{b}{4} \)
4 x (8b + 7) > b
(4 x 8b) + (4 x 7) > b
32b + 28 > b
32b + 28 - b > 0
32b - b > -28
31b > -28
b > \( \frac{-28}{31} \)
b > -\(\frac{28}{31}\)


3

A(n) __________ is two expressions separated by an equal sign.

76% Answer Correctly

formula

expression

problem

equation


Solution

An equation is two expressions separated by an equal sign. The key to solving equations is to repeatedly do the same thing to both sides of the equation until the variable is isolated on one side of the equal sign and the answer on the other.


4

Which of the following statements about a triangle is not true?

57% Answer Correctly

area = ½bh

exterior angle = sum of two adjacent interior angles

sum of interior angles = 180°

perimeter = sum of side lengths


Solution

A triangle is a three-sided polygon. It has three interior angles that add up to 180° (a + b + c = 180°). An exterior angle of a triangle is equal to the sum of the two interior angles that are opposite (d = b + c). The perimeter of a triangle is equal to the sum of the lengths of its three sides, the height of a triangle is equal to the length from the base to the opposite vertex (angle) and the area equals one-half triangle base x height: a = ½ base x height.


5

Solve for z:
6z + 1 > 5 + 8z

54% Answer Correctly
z > -1\(\frac{1}{2}\)
z > -3\(\frac{1}{2}\)
z > -2
z > \(\frac{1}{5}\)

Solution

To solve this equation, repeatedly do the same thing to both sides of the equation until the variable is isolated on one side of the > sign and the answer on the other.

6z + 1 > 5 + 8z
6z > 5 + 8z - 1
6z - 8z > 5 - 1
-2z > 4
z > \( \frac{4}{-2} \)
z > -2